At a wedding reception, the bride and groom and eight attendants will form a receiving line. How many ways can they be arranged in each of following cases? a) Any order will do. b) The bride and groom must be the last two in line. c) The groom must be last in line with the bride next to him. a) In how many ways can the receiving line be formed if any order will do?

Step 1 ：In this case, we are looking at a permutation problem. We have 10 people (the bride, the groom, and 8 attendants) and we want to know how many ways we can arrange them in a line. This is a simple permutation problem where we have 10 items and we want to arrange all of them. The formula for permutations is n!, where n is the number of items. So in this case, we need to calculate 10!.

Step 2 ：Calculate the factorial of 10: \(10!\)

Step 3 ：\(10! = 3628800\)

Step 4 ：Final Answer: There are \(\boxed{3628800}\) ways to arrange the bride, the groom, and the eight attendants in a line if any order will do.