Step 1 :The given probability distribution is as follows: \[\begin{tabular}{|c|r|} \hline$x$ & $P(x)$ \\ \hline 0 & 0.05 \\ \hline 1 & 0.15 \\ \hline 2 & 0.3 \\ \hline 3 & 0.5 \\ \hline \end{tabular}\]
Step 2 :The mean of a probability distribution is calculated by multiplying each outcome by its probability and then summing these products. The formula for the mean is: \[\mu = \sum_{i=0}^{3} x_i \cdot P(x_i)\] where $x_i$ is the outcome and $P(x_i)$ is the probability of that outcome.
Step 3 :Substitute the given values into the formula: \[\mu = (0 \times 0.05) + (1 \times 0.15) + (2 \times 0.3) + (3 \times 0.5)\]
Step 4 :Simplify the expression to find the mean: \[\mu = 2.25\]
Step 5 :Round the mean to one decimal place: \[\mu = 2.3\]
Step 6 :Final Answer: The mean of this probability distribution is \(\boxed{2.3}\)