$\log \left(x^{2}-7 x+11\right)<0$

Step 1 ：Rewrite the inequality as: \(x^2 - 7x + 10 < 0\)

Step 2 ：Find the roots of the quadratic equation: \(x^2 - 7x + 10 = 0\)

Step 3 ：Use the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where a = 1, b = -7, and c = 10

Step 4 ：Calculate the roots: \(x_1 = 2.0\) and \(x_2 = 5.0\)

Step 5 ：Since the inequality is less than 0, find the interval between the roots where the inequality holds true

Step 6 ：\(\boxed{2 < x < 5}\)