Find the $7^{\text {th }}$ term of the geometric sequence whose common ratio is $\frac{3}{2}$ and whose first term is 4 .

Step 1 ：Given a geometric sequence with first term \(a = 4\), common ratio \(r = \frac{3}{2}\), and we want to find the 7th term \(T_7\).

Step 2 ：Use the formula for the nth term of a geometric sequence: \(T_n = a \times r^{n-1}\).

Step 3 ：Plug in the values: \(T_7 = 4 \times \left(\frac{3}{2}\right)^{7-1}\).

Step 4 ：Simplify the exponent: \(T_7 = 4 \times \left(\frac{3}{2}\right)^6\).

Step 5 ：Calculate the final answer: \(T_7 = 45.5625\).

Step 6 ：Final Answer: \(\boxed{45.5625}\)