Rationalise and simplify $\frac{\sqrt{3}-7}{\sqrt{3}+1}$ Give your answer in the form $a+b \sqrt{3}$ where $a$ and $b$ are integers.

Step 1 ：Multiply the numerator and denominator by the conjugate of the denominator: \(\frac{(-7 + \sqrt{3})(\sqrt{3}-1)}{(1 + \sqrt{3})(\sqrt{3}-1)}\)

Step 2 ：Simplify the expression: \(\boxed{5 - 4\sqrt{3}}\)