Charles wants to verify the identity $\csc x \tan x=\sec x$
When verifying that the current identity is true for $x=\frac{\pi}{6}$ rad, the LHS of the equation, to the nearest hundredth, will equal
Solution
Step 1 :Find the values of \(\csc x\), \(\tan x\), and \(\sec x\) when \(x = \frac{\pi}{6}\) rad
Step 2 :Calculate the LHS of the equation, which is \(\csc x \tan x\), and round it to the nearest hundredth: \(\boxed{1.15}\)