Step 1 :First, graph the constraints to find the feasible region. The constraints are: \(x+y \leq 2\), \(x+3y \leq 4\), \(4x+5y \geq 20\), and \(x, y \geq 0\).
Step 2 :Next, find the vertices of the feasible region. These are the points where the constraint lines intersect. The vertices are (0,2), (0,4/3), (4/7, 6/7), and (20/9, 0).
Step 3 :Substitute these vertices into the objective function \(P=6x+12y\) to find the maximum and minimum values.
Step 4 :For (0,2), \(P=6(0)+12(2)=24\).
Step 5 :For (0,4/3), \(P=6(0)+12(4/3)=16\).
Step 6 :For (4/7, 6/7), \(P=6(4/7)+12(6/7)=24\).
Step 7 :For (20/9, 0), \(P=6(20/9)+12(0)=40/3\).
Step 8 :The maximum value of \(P\) is 24.
Step 9 :\(\boxed{P=24}\) is the final answer.