Step 1 :Given the data of pH of rainwater for 12 random samples: 5.20, 5.72, 4.89, 4.80, 5.02, 4.57, 4.74, 5.19, 5.29, 4.76, 4.56, 5.69.
Step 2 :Calculate the sample mean (\(\bar{x}\)) and the sample standard deviation (s). The sample mean is 5.035833333333333 and the sample standard deviation is 0.3926010775082082.
Step 3 :Calculate the t-score for a two-tailed test with \(\alpha = 0.05\) and \(n-1\) degrees of freedom. The t-score is 2.200985160082949.
Step 4 :Use the formula for a confidence interval: \(\bar{x} \pm t_{\alpha/2, n-1} \cdot \frac{s}{\sqrt{n}}\).
Step 5 :Substitute the values into the formula to get the confidence interval: (4.786386509472255, 5.285280157194411).
Step 6 :Round the confidence interval to two decimal places to get: (4.79, 5.29).
Step 7 :Final Answer: The 95% confidence interval for the mean pH of rainwater is between 4.79 and 5.29. Therefore, there is 95% confidence that the population mean pH of rain water is between \(\boxed{4.79}\) and \(\boxed{5.29}\).