Problem

How high can a \( 40 \mathrm{~N} \) force move a load, when \( 395 \mathrm{~J} \) of work is done?

Solution

Step 1 :\(W = Fd\cos(\theta)\)

Step 2 :\(d = \frac{W}{F}\)

Step 3 :\(d = \frac{395\mathrm{~J}}{40\mathrm{~N}}\)

From Solvely APP
Source: https://solvelyapp.com/problems/29589/

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