Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is $\mu=18.00 \mathrm{Mbps}$. The sample size is $n=21$ and the test statistic is $\mathrm{t}=1.826$. P-value $=\square$ (Round to three decimal places as needed.)

Step 1 ：We are given the claim that for a smartphone carrier's data speeds at airports, the mean is \(\mu=18.00 \mathrm{Mbps}\).

Step 2 ：The sample size is \(n=21\) and the test statistic is \(\mathrm{t}=1.826\).

Step 3 ：The P-value is the probability that a random variable is greater than the observed value.

Step 4 ：In this case, we can use the cumulative distribution function (CDF) of the t-distribution to find the probability that t is less than or equal to the observed value, and then subtract this from 1 to find the P-value.

Step 5 ：The degrees of freedom is the sample size minus 1, which is \(df = 20\).

Step 6 ：Using a t-distribution calculator, we find that the cumulative probability associated with t = 1.826 and df = 20 is approximately 0.9585907029911419.

Step 7 ：Subtracting this from 1 gives us the P-value, which is approximately 0.04140929700885809.

Step 8 ：Rounding to three decimal places, the P-value is \(\boxed{0.041}\).