Solve $e^{2 \mathrm{t}}=1800$ for $\mathrm{t}$. $t \approx$ (Round to three decimal places as needed.)

Step 1 ：The given equation is \(e^{2t} = 1800\).

Step 2 ：Take the natural logarithm (ln) on both sides of the equation to get \(2t = ln(1800)\).

Step 3 ：Isolate t by dividing both sides of the equation by 2 to get \(t = \frac{ln(1800)}{2}\).

Step 4 ：Calculate to get \(t \approx 3.748\).

Step 5 ：Final Answer: \(\boxed{3.748}\)