Step 1 :The function given is \(h(x) = 5x^3 - 15x\).
Step 2 :To find the relative extrema, we need to find the critical points of the function. Critical points occur where the derivative of the function is zero or undefined.
Step 3 :The derivative of the function \(h(x) = 5x^3 - 15x\) is \(h'(x) = 15x^2 - 15\).
Step 4 :Setting this equal to zero gives us the critical points \(x = -1\) and \(x = 1\).
Step 5 :We can determine whether each point is a relative maximum, a relative minimum, or neither by using the second derivative test. The second derivative of the function is \(h''(x) = 30x\).
Step 6 :If the second derivative at a critical point is positive, the point is a relative minimum. If it's negative, the point is a relative maximum. If it's zero, the test is inconclusive.
Step 7 :Applying the second derivative test, we find that the point \((-1, 10)\) is a relative maximum and the point \((1, -10)\) is a relative minimum.
Step 8 :\(\boxed{\text{Final Answer: The relative minimum point is (1, -10) and the relative maximum point is (-1, 10).}}\)