Step 1 :Let's create three equations of the form $a x+b y+c z=d$, where $a, b, c$, and $d$ are constants (integers between -5 and 5). For example, we can have the following equations:
Step 2 :\[x + 2y - z = -1\]
Step 3 :\[2x - y + z = 2\]
Step 4 :\[x - 2y + z = -1\]
Step 5 :We can represent these equations in matrix form as follows:
Step 6 :\[\begin{bmatrix} 1 & 2 & -1 \\ 2 & -1 & 1 \\ 1 & -2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -1 \\ 2 \\ -1 \end{bmatrix}\]
Step 7 :We can perform row operations on this matrix to obtain a row-echelon form and find the solution to the system of equations.
Step 8 :After performing the row operations, we find that the solution to the system of equations is \(x = -1\), \(y = 4\), and \(z = 8\).
Step 9 :Each of these equations represents a plane in the 3D space. The solution to the system of equations is the intersection of these planes. If the planes intersect at a single point, the system has a unique solution. If the planes intersect along a line, the system has infinitely many solutions. If the planes do not intersect, the system has no solution.
Step 10 :This geometric interpretation can be visualized using the GeoGebra 3D calculator.
Step 11 :Final Answer: The solution to the system of equations is \(\boxed{-1, 4, 8}\).