(B) \[ \left\{\begin{array}{l} 2 x-3 y-z=0 \\ -2 x+y+2 z=-9 \\ 4 x+2 y+z=1 \end{array}\right. \]

Step 1 ：\(\left\{\begin{array}{l} 2x-3y-z=0 \\ -2x+y+2z=-9 \\ 4x+2y+z=1 \end{array}\right.\)

Step 2 ：Use matrix operations to solve the system of linear equations.

Step 3 ：\(\begin{bmatrix} 2 & -3 & -1 \\ -2 & 1 & 2 \\ 4 & 2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 0 \\ -9 \\ 1 \end{bmatrix}\)

Step 4 ：\(\begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 0.5 \\ 2 \\ -5 \end{bmatrix}\)

Step 5 ：\(\boxed{x = 0.5, y = 2, z = -5}\)