Step 1 :The function given is \(f(x) = 4 + x + x^{2}\).
Step 2 :First, we find the derivative of the function, \(f'(x) = 2x + 1\).
Step 3 :The critical points of the function are the solutions to \(f'(x) = 0\). Solving this equation gives us \(x = -1/2\).
Step 4 :We then find the second derivative of the function, \(f''(x) = 2\).
Step 5 :Since \(f''(-1/2) > 0\), the point \(x = -1/2\) is a relative minimum.
Step 6 :The function is increasing where its derivative is positive, which is when \(x > -1/2\), and decreasing where its derivative is negative, which is when \(x < -1/2\).
Step 7 :Thus, the relative minimum point is \((-1/2, 15/4)\) and there are no relative maximum points. The function is increasing for \(x > -1/2\) and decreasing for \(x < -1/2\).
Step 8 :Final Answer: \(\boxed{\text{The relative minimum point is } (-1/2, 15/4) \text{ and there are no relative maximum points. The function is increasing for } x > -1/2 \text{ and decreasing for } x < -1/2.}\)