The demand for a new computer game can be modeled by $p(x)=43-5 \ln x$, for $0 \leq x \leq 800$, where $p(x)$ is the price consumers will pay, in dollars, and $x$ is the number of games sold, in thousands. Recall that total revenue is given by $R(x)=x \cdot p(x)$. Complete parts (a) through (c) below. a) Find $R(x)$. \[ R(x)= \]

Step 1 ：Given the price function $p(x)=43-5 \ln x$, where $p(x)$ is the price consumers will pay, in dollars, and $x$ is the number of games sold, in thousands.

Step 2 ：We are asked to find the total revenue function $R(x)$, which is given by $R(x)=x \cdot p(x)$.

Step 3 ：Substitute $p(x)$ into the revenue function to get $R(x)=x(43-5 \ln x)$.

Step 4 ：\(\boxed{R(x)=x(43-5 \ln x)}\)