The one-to-one functions $g$ and $h$ are defined as follows. \[ \begin{array}{l} g=\{(-5,5),(0,-7),(5,4),(7,0)\} \\ h(x)=3 x+14 \end{array} \] Find the following. $g^{-1}(5)=\square$ $h^{-1}(x)=\square$ $\left(h^{-1} \circ h\right)(-5)=\square$

Step 1 ：The first question asks for the inverse of function g at 5. This means we need to find the x-value that corresponds to the y-value of 5 in the function g. Looking at the function g, we can see that the pair (-5,5) is present. This means that \(g^{-1}(5)\) is -5.

Step 2 ：The second question asks for the inverse of function h. The function h is given as \(h(x) = 3x + 14\). To find the inverse of this function, we need to swap x and y and solve for y. This will give us the inverse function \(h^{-1}(x)\).

Step 3 ：The third question asks for the value of \((h^{-1} ∘ h)(-5)\). This is the composition of the inverse of h and h at -5. Since the inverse of a function undoes the operation of the function, the composition of a function and its inverse will just give the original input. Therefore, \((h^{-1} ∘ h)(-5)\) should be -5.

Step 4 ：Final Answer: \(g^{-1}(5) = \boxed{-5}\), \(h^{-1}(x) = \boxed{\frac{x - 14}{3}}\), \((h^{-1} ∘ h)(-5) = \boxed{-5}\)