Step 1 :The equilibrium position of a mass-spring system is the position where the spring force balances the gravitational force, which is usually defined as \(x=0\).
Step 2 :The initial position of the mass is given as \(x(0)=-4\), which means the mass is 4 units to the left of the equilibrium position at \(t=0\).
Step 3 :The initial velocity of the mass is given as \(\dot{x}(0)=-3\), which means the mass is moving to the left at \(t=0\) (since negative velocity indicates leftward motion in this context).
Step 4 :Final Answer: The mass is \(\boxed{4}\) units to the left of its equilibrium position when \(t=0\) and it is moving to the \(\boxed{left}\) at that time.