Problem

6a) Plot the following points: $\mathrm{A}(8,-2), \mathrm{B}(8,4)$, $\mathrm{C}(-1,4)$ 6b) Perform a scale factor of $1 / 3$, keeping $C$ in the same place. Dilatation $\rightarrow B^{\prime}=(\quad, \quad)$

Solution

Step 1 :Find the vector from point C to point B: \(\vec{CB} = (8 - (-1), 4 - 4) = (9, 0)\)

Step 2 :Multiply the vector by the scale factor: \(\vec{CB'} = \frac{1}{3} \vec{CB} = (3, 0)\)

Step 3 :Add the scaled vector to point C: \(B' = C + \vec{CB'} = (-1 + 3, 4 + 0) = (2, 4)\)

Step 4 :\boxed{B' = (2, 4)}

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Source: https://solvelyapp.com/problems/25920/

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