Find the area between the curves. \[ x=-2, x=2, y=9 x, y=x^{2}-10 \] Set up the integral (or integrals) needed to compute this area. Use the smallest possible number of integrals. Select the correct choice below and fill in the answer boxes to complete your choice. A. B. $\mathrm{dx}$

Step 1 ：The area between two curves is given by the integral of the absolute difference between the two functions. In this case, the two functions are \(y = 9x\) and \(y = x^2 - 10\).

Step 2 ：We need to find the points of intersection of these two curves to determine the limits of integration. The points of intersection are at x = -1 and x = 10. However, we are only interested in the region between x = -2 and x = 2.

Step 3 ：Therefore, we need to set up two integrals: one from -2 to -1 and another from -1 to 2. In the first integral, \(y = 9x\) is above \(y = x^2 - 10\), and in the second integral, \(y = x^2 - 10\) is above \(y = 9x\).

Step 4 ：The area between the curves is given by the sum of the two integrals.

Step 5 ：Final Answer: \(\boxed{\int_{-2}^{-1} |9x - (x^2 - 10)| dx + \int_{-1}^{2} |(x^2 - 10) - 9x| dx}\)