Step 1 :The problem is a binomial distribution problem. The binomial distribution is used when there are exactly two mutually exclusive outcomes of a trial. These outcomes are labeled 'success' and 'failure'. We are asked to find the mean and standard deviation of the distribution.
Step 2 :The mean of a binomial distribution is given by np where n is the number of trials and p is the probability of success. In this case, n = 130 (the number of individuals) and p = 0.98 (the probability of finding relief from sinusitis).
Step 3 :The standard deviation of a binomial distribution is given by \(\sqrt{np(1-p)}\) where n is the number of trials, p is the probability of success and (1-p) is the probability of failure.
Step 4 :Given n = 130 and p = 0.98, we can calculate the mean as \(np = 130 \times 0.98 = 127.4\)
Step 5 :We can also calculate the standard deviation as \(\sqrt{np(1-p)} = \sqrt{130 \times 0.98 \times (1-0.98)} = 1.596\)
Step 6 :Final Answer: The estimated number of individuals in the random sample who do not find relief from their sinusitis is \(\boxed{127.4}\) and the standard deviation of the distribution is \(\boxed{1.596}\).