Find the solution of the logarithmic equation \[ 6-\ln (3-x)=0 \] correct to four decimal places. Your answer is \[ x= \]

Step 1 ：Subtract 6 from both sides of the equation to isolate the logarithm: \(-\ln (3-x) = -6\)

Step 2 ：Multiply both sides of the equation by -1 to get rid of the negative sign: \(\ln (3-x) = 6\)

Step 3 ：Convert the logarithmic equation to an exponential equation: \(3-x = e^6\)

Step 4 ：Solve for x by subtracting \(e^6\) from both sides of the equation and multiplying by -1: \(x = 3 - e^6\)

Step 5 ：Calculate the value of \(e^6\) and subtract it from 3 to find the value of x: \(x = -400.4287934927351\)

Step 6 ：Final Answer: The solution to the logarithmic equation is \(\boxed{-400.4288}\)