Step 1 :Use the one-to-one property of logarithms to set the two sides of the equation equal to each other: \(7(7x^2 - 6) = 127\).
Step 2 :Simplify the equation to get: \(49x^2 - 42 = 127\).
Step 3 :Solve the equation to get two solutions: \(x = -\frac{13}{7}\) and \(x = \frac{13}{7}\).
Step 4 :Since the domain of the logarithm function is \((0, \infty)\), we can't have a negative argument for the logarithm. Therefore, the only valid solution is \(x = \frac{13}{7}\).
Step 5 :So, the final answer is \(x = \boxed{\frac{13}{7}}\).