Step 1 :The null hypothesis is that the standard deviation is equal to 3%, and the alternative hypothesis is that the standard deviation is less than 3%.
Step 2 :We are given a sample standard deviation of 2.04% from a sample of 21 months.
Step 3 :We can use a chi-square test to test the hypotheses. The test statistic is calculated as \((n-1)\times (\text{sample standard deviation})^2 / (\text{population standard deviation})^2\), where n is the sample size.
Step 4 :After calculating, the test statistic is approximately 9.25.
Step 5 :We can use a chi-square distribution with n-1 degrees of freedom to find the p-value.
Step 6 :The p-value is approximately 0.98.
Step 7 :Since the p-value is greater than the significance level of 0.05, we fail to reject the null hypothesis.
Step 8 :This means that there is not sufficient evidence to conclude that the fund has moderate risk at the 0.05 level of significance.
Step 9 :Final Answer: The test statistic is \(\boxed{9.25}\) and the p-value is \(\boxed{0.98}\). Since the p-value is greater than the level of significance, we fail to reject the null hypothesis. There is not sufficient evidence to conclude that the fund has moderate risk at the 0.05 level of significance.