$2 x^{2}-5 x+3$

Step 1 ：This is a quadratic equation of the form \(ax^2 + bx + c\).

Step 2 ：The roots of this equation can be found using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).

Step 3 ：Given that a = 2, b = -5, and c = 3.

Step 4 ：Calculate the discriminant (D) using the formula \(D = b^2 - 4ac\). In this case, D = 1.

Step 5 ：Substitute the values of a, b, and D into the quadratic formula to find the roots of the equation.

Step 6 ：The roots of the equation are x1 = 1.5 and x2 = 1.0.

Step 7 ：Final Answer: The roots of the equation \(2 x^{2}-5 x+3\) are \(\boxed{1.5}\) and \(\boxed{1.0}\).