Problem
For the function $f(x)=4 x+2$, find $f^{-1}(x)$.
Solution
Step 1 ：Switch the roles of x and y: \(x = 4y + 2\)
Step 2 ：Solve for y: \(y = \frac{x - 2}{4}\)
Step 3 ：\(\boxed{f^{-1}(x) = \frac{x - 2}{4}}\)
Step 1 ：Switch the roles of x and y: \(x = 4y + 2\)
Step 2 ：Solve for y: \(y = \frac{x - 2}{4}\)
Step 3 ：\(\boxed{f^{-1}(x) = \frac{x - 2}{4}}\)
