Problem
For the function $f(x)=\sqrt[3]{x}+4$, find $f^{-1}(x)$.
Solution
Step 1 ：Given function: \(y = \sqrt[3]{x} + 4\)
Step 2 ：Swap x and y: \(x = \sqrt[3]{y} + 4\)
Step 3 ：Solve for y: \(y = (x - 4)^3\)
Step 4 ：Final Answer: \(\boxed{f^{-1}(x) = (x - 4)^3}\)
