Step 1 :The given differential equation is \(y^{\prime \prime}+81 y=6 t^{3} \sin 9 t\).
Step 2 :The auxiliary equation of the given differential equation is obtained by replacing each derivative with a power of 'm'. So, for the given differential equation, the auxiliary equation would be \(m^2 + 81 = 0\).
Step 3 :We need to solve this equation for 'm' to find the roots. The coefficients are a = 1, b = 0, c = 81.
Step 4 :The discriminant D is calculated as \(D = b^2 - 4ac = -324\).
Step 5 :The roots of the auxiliary equation are complex numbers, specifically ±9j. These roots indicate that the solution to the differential equation will involve sine and cosine functions.
Step 6 :Final Answer: The roots of the auxiliary equation associated with the given differential equation are \(\boxed{-9j, 9j}\).