Step 1 :We are given the matrix equation \(\left[\begin{array}{cc} A & B \\ C & 0 \end{array}\right]\left[\begin{array}{cc} I & 0 \\ X & Y \end{array}\right] = \left[\begin{array}{ll} 0 & I \\ Z & 0 \end{array}\right]\).
Step 2 :We multiply the matrices on the left side to get \(\left[\begin{array}{cc} AI + BX & BY \\ CI & 0 \end{array}\right]\).
Step 3 :We set this equal to the matrix on the right side of the equation to get \(\left[\begin{array}{cc} AI + BX & BY \\ CI & 0 \end{array}\right] = \left[\begin{array}{ll} 0 & I \\ Z & 0 \end{array}\right]\).
Step 4 :From this, we can form the following equations: \(AI + BX = 0\), \(BY = I\), \(CI = Z\), and \(0 = 0\).
Step 5 :Solving these equations, we find that \(X = -\frac{A \cdot I}{B}\), \(Y = \frac{I}{B}\), and \(Z = C \cdot I\).
Step 6 :Thus, the solutions for X, Y, and Z are \(\boxed{X = -\frac{A \cdot I}{B}}\), \(\boxed{Y = \frac{I}{B}}\), and \(\boxed{Z = C \cdot I}\).