The population of a town is 2500 and is decreasing at a rate of $3 \%$ per year. Write an exponential decay function for the population of the town atter $t$ ears. $f(t)=0.97(2500)^{t}$ $f(t)=2500(.97)^{t}$ $f(t)=.97 t+2500$ $f(t)=2500(.7)^{t}$ Previous

Step 1 ：The question is asking for an exponential decay function. The general form of an exponential decay function is \(f(t) = a(1 - r)^t\), where \(a\) is the initial amount, \(r\) is the rate of decay, and \(t\) is time.

Step 2 ：In this case, the initial population is 2500, and the rate of decay is 3% or 0.03.

Step 3 ：Therefore, the function should be \(f(t) = 2500(1 - 0.03)^t\).

Step 4 ：The exponential decay function for the population of the town after \(t\) years is \(\boxed{f(t) = 2500(1 - 0.03)^t}\).