Step 1 :Find the dot product of the two vectors: \(\vec{a} \cdot \vec{b} = (2)(1) + (-3)(-1) + (4)(0) = 5\)
Step 2 :Find the magnitude of vector \(\vec{b}\): \(||\vec{b}|| = \sqrt{(1)^2 + (-1)^2 + (0)^2} = \sqrt{2}\)
Step 3 :Calculate the scalar magnitude of the projection: \(\frac{\vec{a} \cdot \vec{b}}{||\vec{b}||} = \frac{5}{\sqrt{2}} = \frac{5\sqrt{2}}{2}\)
Step 4 :\(\boxed{\text{Final Answer: }\frac{5\sqrt{2}}{2}}\)