In $\triangle \mathrm{PQR}, \mathrm{m} \angle P=(x+13)^{\circ}, \mathrm{m} \angle Q=(10 x+13)^{\circ}$, and $\mathrm{m} \angle R=(2 x-2)^{\circ}$. Find $m \angle Q$.

Step 1 ：Given a triangle PQR, where the measure of angle P is \((x+13)^{\circ}\), the measure of angle Q is \((10x+13)^{\circ}\), and the measure of angle R is \((2x-2)^{\circ}\).

Step 2 ：We know that the sum of the angles in a triangle is always 180 degrees. Therefore, we can set up the equation \((x+13) + (10x+13) + (2x-2) = 180\) and solve for x.

Step 3 ：Solving the equation gives us the value of x as 12.

Step 4 ：Substituting x = 12 into the expression for m∠Q, we get m∠Q = 133 degrees.

Step 5 ：So, the measure of angle Q is \(\boxed{133^{\circ}}\).