8. Jeff travels $2 \mathrm{~h}$ by car and $3 \mathrm{~h}$ by bus. The average speed of the bus is $20 \mathrm{~km} / \mathrm{k}$ slower than that of the car, and he goes $40 \mathrm{~km}$ farther by bus. What was the average speed of the car, and how far was Jeff's entire trip?

Step 1 ：Let x be the average speed of the car in km/h, and the average speed of the bus is (x - 20) km/h.

Step 2 ：Distance traveled by car = 2x, and distance traveled by bus = 3(x - 20).

Step 3 ：Set up the equation: 3(x - 20) = 2x + 40.

Step 4 ：Solve for x: x = 100.

Step 5 ：Find the average speed of the bus: (100 - 20) = 80 km/h.

Step 6 ：Find the distance traveled by car: 2(100) = 200 km.

Step 7 ：Find the distance traveled by bus: 3(80) = 240 km.

Step 8 ：Find the total distance of Jeff's trip: 200 + 240 = \(\boxed{440}\) km.