Problem

D) $x$ can be all real numbers 7. If $x+6 \geq 5 x-2$, which of the following inequalities gives all possible values for $x+1$ ? A) $x+1 \leq 2$ B) $x+1 \geq 3$ C) $x+1 \leq 3$ D) $x+1 \geq 2$

Solution

Step 1 :Solve the inequality \(x+6 \geq 5x-2\) for \(x\)

Step 2 :Subtract \(x\) from both sides: \(6 \geq 4x-2\)

Step 3 :Add \(2\) to both sides: \(8 \geq 4x\)

Step 4 :Divide both sides by \(4\): \(2 \geq x\)

Step 5 :Find the possible values for \(x+1\)

Step 6 :Since \(x \leq 2\), then \(x+1 \leq 3\)

Step 7 :\(\boxed{x+1 \leq 3}\)

From Solvely APP
Source: https://solvelyapp.com/problems/21969/

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