Step 1 :Solve the inequality \(x+6 \geq 5x-2\) for \(x\)
Step 2 :Subtract \(x\) from both sides: \(6 \geq 4x-2\)
Step 3 :Add \(2\) to both sides: \(8 \geq 4x\)
Step 4 :Divide both sides by \(4\): \(2 \geq x\)
Step 5 :Find the possible values for \(x+1\)
Step 6 :Since \(x \leq 2\), then \(x+1 \leq 3\)
Step 7 :\(\boxed{x+1 \leq 3}\)