Convert the rectangular coordinates $(\sqrt{3},-1)$ into polar form. Express the angle using radians in terms of $\pi$ over the interval $0 \leq \theta<2 \pi$, with a positive value of $r$.

Step 1 ：Find the distance from the origin (r) using the formula: \(r = \sqrt{x^2 + y^2}\)

Step 2 ：Find the angle (θ) using the arctangent function: \(θ = \arctan(\frac{y}{x})\) and make sure it is within the interval \(0 \leq θ < 2π\)

Step 3 ：The polar form of the rectangular coordinates \((\sqrt{3},-1)\) is \(\boxed{(2, \frac{11\pi}{6})}\)