11 Solve the quadratic equation \( x^{2}-6 x+13=0 \) A \( 3-2 i \) or \( 3+2 \hat{i} \) \( B-3-2 i \) or \( -3+2 i \) C -1.690 or 7.690 D -7.690 or 1.690

Step 1 ：Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a} \) with a = 1, b = -6, and c = 13.

Step 2 ：Compute the discriminant, \( \Delta = b^{2} - 4ac = (-6)^{2} - 4 (1) (13) = 36 - 52 = -16. \)

Step 3 ：Find the solutions, \( x = \frac{-(-6) \pm \sqrt{-16}}{2(1)} = \frac{6 \pm 4i}{2} = 3 \pm 2i. \)