Problem
$\frac{c^{2}+6 c+8}{c^{2}-5 c-14} ?$
Solution
Step 1 ：Factor the numerator and denominator: \(\frac{(c+2)(c+4)}{(c-7)(c+2)}\)
Step 2 ：Simplify the expression: \(\boxed{\frac{c+4}{c-7}}\)
Step 1 ：Factor the numerator and denominator: \(\frac{(c+2)(c+4)}{(c-7)(c+2)}\)
Step 2 ：Simplify the expression: \(\boxed{\frac{c+4}{c-7}}\)
