Problem
The final velocity, $V$, of an object under constant acceleration can be found using the formula $V^{2}=v^{2}+2 a s$, where $v$ is the initial velocity (in meters per second), $a$ is acceleration (in meters per second), and $s$ is the distance (in meters). What is the formula solved for $a$ ? $v^{2}-v^{2}-2 s=a$ $v^{2}-v^{2}+2 s=a$ $\frac{v^{2}-v^{2}}{2 s}=a$ $\frac{v^{2}+v^{2}}{2 s}=a$ Mark this and return Save and Exit Next Submit
Solution
Step 1 ：Subtract \(v^2\) from both sides: \(V^2 - v^2 = 2as\)
Step 2 ：Divide both sides by \(2s\): \(a = \boxed{\frac{V^2 - v^2}{2s}}\)
