Problem
The final velocity, $V$, of an object under constant acceleration can be found using the formula $V^{2}=v^{2}+2 a s$, where $V$ the initial velocity (in meters per second), $a$ is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for $a$ ? $v^{2}-v^{2}-2 s=a$ $v^{2}-v^{2}+2 s=a$ $\frac{v^{2}-v^{2}}{2 s}=a$ $\frac{v^{2}+v^{2}}{2 s}=a$
Solution
Step 1 ：Given formula: \(V^2 = v^2 + 2as\)
Step 2 ：Isolate 'a': \(a = \frac{V^2 - v^2}{2s}\)
Step 3 ：Final Answer: \(\boxed{a = \frac{V^2 - v^2}{2s}}\)
