Problem
Write a recursive formula for \( a_{n} \), the \( n^{\text {th }} \) term of the sequence \( 1,6,36,216, \ldots \) \( a_{1}= \) \( a_{n}= \) Submit Answer \( a_{n-1} \)
Solution
Step 1 ：\(a_{1}=1\)
Step 2 ：\(a_{n}=6a_{n-1}\)
