Problem
The function \( f(t)=4600(0.9)^{\frac{t}{24}} \) represents the change in a quantity over \( t \) days. What does the constant 0.9 reveal about the rate of change of the quantity? The function is exponentially at a rate of \( \% \) every
Solution
Step 1 ：Evaluate decay factor: 0.9.
Step 2 ：Convert decay factor to percentage: (1 - 0.9) * 100.
Step 3 ：Evaluate percentage: (1 - 0.9) * 100 = 10%
