Problem

10 Consider the quadratic equation below: \[ 5 x^{2}+12 x-216 \] Part A What are the values of $a, b$, and $c$ ? \[ \begin{array}{l} a=5 \\ b=12 \\ c=-216 \end{array} \] Part B What is the axis of symmetry? (Write your answer as a DECIMAL!) \[ \boldsymbol{x}= \]

Solution

Step 1 :Given the quadratic equation: \(5x^2 + 12x - 216\)

Step 2 :Identify the coefficients: \(a = 5, b = 12, c = -216\)

Step 3 :Find the axis of symmetry using the formula: \(x = \frac{-b}{2a}\)

Step 4 :Substitute the values of a and b: \(x = \frac{-12}{2 \times 5}\)

Step 5 :Simplify the expression: \(x = -1.2\)

Step 6 :\(\boxed{\text{Final Answer:}}\)

Step 7 :Part A: \(a = 5, b = 12, c = -216\)

Step 8 :Part B: \(\text{Axis of symmetry: } x = -1.2\)

From Solvely APP
Source: https://solvelyapp.com/problems/21197/

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