\( \frac{1}{6} x+\frac{2}{3}=\frac{1}{4} x-\frac{1}{3} \)

Step 1 ：\( \frac{1}{4}x - \frac{1}{6}x = \frac{2}{3} + \frac{1}{3} \)

Step 2 ：\( \frac{1}{12}x = \frac{3}{3} \)

Step 3 ：\( x = \frac{12}{1} \)