Problem
A child's game uses the spinner shown. What is the probability that in two consecutive spins, the first outcome is red and the second outcome is blue? \( \frac{1}{2} \) \( \frac{1}{4} \) \( \frac{1}{12} \) \( \frac{1}{16} \)
Solution
Step 1 ：\( P(\text{Red}) = \frac{1}{2} \)
Step 2 ：\( P(\text{Blue}) = \frac{1}{4} \)
Step 3 ：\( P(\text{Red and Blue}) = \frac{1}{2} \times\frac{1}{4} = \frac{1}{8} \)
