Step 1 :For part a, we have a gradient of -1 and a y-intercept of 4. We can use the equation of a straight line, y = mx + c, and plug in the given values to find the equation: \(y = -1x + 4\)
Step 2 :For part b, we have a gradient of \(\frac{3}{4}\) and a y-intercept of \(-\frac{1}{2}\). We can use the equation of a straight line, y = mx + c, and plug in the given values to find the equation: \(y = \frac{3}{4}x - \frac{1}{2}\)
Step 3 :\(\boxed{\text{Final Answer:}}\) \(\boxed{\text{a. }} y = -1x + 4\) \(\boxed{\text{b. }} y = \frac{3}{4}x - \frac{1}{2}\)