Problem
A certain television is advertised as a 63-inch TV (the diagonal length). If the height of the TV is 43 inches, how wide is the TV? Round to the nearest tenth of an inch.
Solution
Step 1 ：\( W^2 + 43^2 = 63^2 \)
Step 2 ：\( W^2 = 63^2 - 43^2 \)
Step 3 ：\( W \approx \sqrt{63^2 - 43^2} \)
