Step 1 :Given the function \(h(x)=\log _{3}\left(x^{2}+x\right)\)
Step 2 :We need to find its derivative \(h^{\prime}(x)\)
Step 3 :We use the chain rule, which states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function
Step 4 :In this case, the outer function is the logarithm and the inner function is \(x^{2}+x\)
Step 5 :The derivative of the logarithm base 3 of x is \(\frac{1}{x*\ln(3)}\)
Step 6 :The derivative of \(x^{2}+x\) is \(2x+1\)
Step 7 :So, the derivative of the function \(h(x)=\log _{3}\left(x^{2}+x\right)\) is \(\frac{1}{(x^{2}+x)*\ln(3)}*(2x+1)\)
Step 8 :Finally, we simplify the derivative to get the final answer
Step 9 :\(\boxed{h^{\prime}(x)=\frac{2x+1}{(x^{2}+x)\ln(3)}}\)