Find the quadratic function $y=a x^{2}+b x+c$ whose graph passes through the given points. \[ (-1,-9),(1,-3),(-2,-6) \]

Step 1 ：Given three points (-1,-9), (1,-3), and (-2,-6), we need to find the quadratic function \(y = ax^{2} + bx + c\) that passes through these points.

Step 2 ：Substitute these points into the function to get three equations: \(a - b + c = -9\), \(a + b + c = -3\), and \(4a - 2b + c = -6\).

Step 3 ：Solve these equations to find the values of a, b, and c. The solution is \(a = 2\), \(b = 3\), and \(c = -8\).

Step 4 ：Substitute these values into the quadratic function to get the final answer.

Step 5 ：\(\boxed{y = 2x^{2} + 3x - 8}\)