Step 1 :The null hypothesis is \(H_{0} : \sigma = 0.005\).
Step 2 :The alternative hypothesis is \(H_{1} : \sigma < 0.005\).
Step 3 :Calculate the value of the test statistic using the formula \(\chi^{2} = \frac{(n-1)s^{2}}{\sigma^{2}}\), where n is the sample size, s is the sample standard deviation, and \(\sigma\) is the population standard deviation. In this case, n = 21, s = 0.0033, and \(\sigma\) = 0.005.
Step 4 :The value of the test statistic is \(\chi^{2} = \boxed{8.712}\).
Step 5 :Use technology to determine the P-value for the test statistic. The P-value is \(\boxed{0.986}\).
Step 6 :Compare the P-value to the significance level \(\alpha\). Since the P-value is greater than the significance level of 0.10, we fail to reject the null hypothesis.
Step 7 :There is not enough evidence to conclude that the standard deviation has decreased at the \(\alpha=0.10\) level of significance.