Step 1 :The volume of the solid obtained by rotating a region bounded by the curves \(y=f(x)\) and \(y=g(x)\), where \(f(x) \geq g(x)\), about the x-axis from \(x=a\) to \(x=b\) is given by the formula: \[V = \pi \int_{a}^{b} [f(x)]^2 - [g(x)]^2 dx\]
Step 2 :In this case, the region is bounded by the curves \(y=x+1\) and \(y=0\) from \(x=0\) to \(x=5\). So, we have \(f(x) = x+1\) and \(g(x) = 0\).
Step 3 :We can substitute these into the formula and evaluate the integral to find the volume.
Step 4 :Final Answer: The volume of the solid obtained by rotating the region bounded by the curves \(y=x+1\), \(y=0\), \(x=0\), and \(x=5\) about the x-axis is \(\boxed{\frac{215\pi}{3}}\).